In (I) we obtained the ``implicit'' algebraic differential equation for the function defined by Y=∑∞1naxn1−xn where a is an odd positive integer, and conjectured that there are no algebraic differential equations for the case when a is an even integer. In this note we obtain a simple proof that (this has been known for almost 200 years) Y=∞∑1xn2(|x|<1)
satisfies an algebraic differential equation, and conjecture that Y=∑∞1xnk (where k is a positive bigger than 2) does not satisfy an algebraic differential equation.